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4 June, 16:04

20 mols barium chloride to kg

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Answers (2)
  1. 4 June, 16:19
    0
    BaCl2: 137 + 35.5 x 2 = 208 g/mol

    20 mol x 208 g/mol = 4160 g BaCl2

    1 g = 0.001 kg = > 4160 g = 4.16 kg BaCl2
  2. 4 June, 17:32
    0
    4.1646 kg

    Explanation:

    BaCl2

    M (BaCl2) = 137.33 + 2*35.45 = 208.23 g/mol

    208.23 g/mol * 20 mol=4164.6 g ≈ 4.1646 kg
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