A gas sample occupies 3.25 liters at 297.5K and 2.4 atm. Determine the temperature at which the gas will occupy 4.25 L at 1.50 atm.

For equal moles of gas, temperature can be calculated from ideal gas equation as follows:

P*V=n*R*T ... (1)

Initial volume, temperature and pressure of gas is 3.25 L, 297.5 K and 2.4 atm respectively.

2.4 atm * 3.25 L=n*R*297.5 K

Rearranging,

n/times R=0.0262 atm L/K

Similarly at final pressure and volume from equation (1),

1.5 atm * 4.25 L=n*R*T

Putting the value of n*R in above equation,

1.5 atm * 4.25 L=0.0262 (atm L/K) * T

Thus, T=243.32 K