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24 October, 11:37

What is the empirical formula for a compound that is 43.6% phosphorus

and 56.4% oxygen?

Select one:

O a. P307

O b. PO3

O C. P203

O d. P205

1727 of what is the empirical

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Answers (1)
  1. 24 October, 15:28
    0
    d. P2O5.

    Explanation:

    We find the ratio of the atoms by dividing the percentages by the relative atomic masses:

    P : 43.6 / 30.974 = 1.4076

    O: 56.4 / 15.999 = 3.5252

    1.4076 : 3.5252

    = 1 : 2.5

    = 2:5.

    So the answer is P2O5.
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