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24 June, 09:15

A sample of gas occupied 250.0 mL at 30.0 C. What volume will it have at 60.0 C, assuming the pressure remains constant?

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  1. 24 June, 11:10
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    Answer: 274.75 mL

    Explanation:

    Initial volume of gas V1 = 250.0 mL

    Initial temperature of gas T1 = 30.0 C

    Convert temperature in Celsius to Kelvin

    (30.0°C + 273 = 303K)

    New volume V2 = ?

    New temperature T2 = 60.0 C

    (60.0°C + 273 = 333K)

    Since, volume and temperature are involved while pressure is constant, apply the formula for Charles law

    V1/T1 = V2/T2

    250.0 mL/303K = V2/333K

    Cross multiply

    250.0 mL x 333K = 303K x V2

    83250 = 303V2

    V2 = 83250/303

    V2 = 274.75 mL

    Thus, the volume will be 274.75 mL
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