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21 February, 01:00

Tina has a sample of gaseous water at a temperature of 400 C

and a pressure of 4 atm.

If Tina increases the pressure to 200 atm, will the gaseous water

liquefy? Why or why not?

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Answers (1)
  1. 21 February, 02:05
    0
    The gaseous water will not liquefy since its new temperature is far higher that its initial temperature.

    Explanation:

    To know if the gaseous water will liquefy or not, we must first obtain the new temperature of the water. This can be obtained as follow:

    Step 1:

    Data obtained from the question:

    Initial temperature (T1) = 400°C

    Initial pressure (P1) = 4 atm

    Final pressure (P2) = 200 atm

    Final temperature (T2) = ?

    Step 2:

    Conversion of celsius temperature to Kelvin temperature.

    Temperature (Kelvin) = temperature (celsius) + 273

    Initial temperature (T1) = 400°C = 400°C + 273 = 673K

    Step 3:

    Determination of the final temperature of the water.

    Using the equation P1/T1 = P2/T2, the final temperature can obtain as follow:

    P1/T1 = P2/T2

    4/673 = 200/T2

    Cross multiply to express in linear form

    4 x T2 = 673 x 200

    Divide both side by 4

    T2 = (673 x 200) / 4

    T2 = 33650K

    The final temperature of sample of gaseous water is 33650K

    Step 4:

    Conversion of Kelvin temperature to celsius temperature.

    Temperature (celsius) = temperature (Kelvin) - 273

    Temperature (celsius) = 33650K - 273

    Temperature (celsius) = 33377°C

    Therefore, the sample of the gaseous water will not liquefy since its new temperature is far higher that its initial temperature.
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