2 - A gas has a volume of 500 mL at a temperature of - 73.0 °C. What volume will the gas

occupy at 27.0°C?

750mL

Explanation:

Charles law states that the volume of a fixed mass of gas is inversely proportional to its temperature, at constant pressure

Mathematically,

V1/T1 = V2/T2

Values given are;

V1=initial volume of the gas=500mL

T1=initial temperature of the gas=-73.0°C = (-73.0+273) K=200K

V2=final volume of gas

T2=final temperature of gas=27.0°C = (27.0+273) K=300K

The volume of the gas at 27°C is unknown.

We'll make V2 subject of the formula

V1/T1=V2/T2

V2 = (V1*T2) / T1

V2 = (500*300) / 200

V2=750mL

Therefore, the gas will occupy a volume of 750mL at 27.0°C

Answer: 750ml

Explanation:

Using charle's law

V1/T1=V2/T2

V1 = 500ml

T1 = - 73⁰C

V2=?

T2=27⁰C

We can see that the temperature is in Celsius

Now, we will convert to Kelvin

Kelvin = 273 + Celsius

So convert the Celsius value to Kelvin

For T1 = 273 + (-73)

T1 = 273-73

T1 = 200K

For T2 = 273+27

T2 = 300K

V1/T1=V2/T2

500/200=V2/300

Cross multiply

200*V2=500*300

200V2 = 150000

V2 = 150000/200

V2 = 750ml

So,

750ml of gas will occupy at 27⁰C