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19 February, 13:48

How many moles of Ca[OH]2 are present in 80.0 g of Ca[OH]2?

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  1. 19 February, 16:50
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    1.08mol

    Explanation:

    moles = reacting mass / molecular weight

    reacting mass = 80.0g molecular weight of Ca[OH]2 = 40 + 2 (16 + 1) = 74g/mol

    mole = 80.0/74 = 1.08mol
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