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27 August, 17:01

How many grams of water react to form 7.21 moles of Ca (OH) 2

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Answers (1)
  1. 27 August, 18:05
    0
    You have the stoichiometric equation. This tells you unequivocally that an

    18



    g

    mass of water, 1 mole, reacts with a

    56.07



    g

    mass of quicklime to form a

    74.09



    g

    mass of slaked lime.

    If you don't from where I am getting these numbers, you should know, and someone will be willing to elaborate.

    Here, you have formed

    6.21



    m

    o

    l

    of quicklime which requires stoichiometric lime AND water. And thus you need a mass of

    6.21



    m

    o

    l

    *

    18.01



    g



    m

    o

    l

    -

    1

    water



    88



    g

    .

    In practice, of course I would not weigh out this mass. I would just pour

    100

    -

    200



    m

    L

    of water into the lime.
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