How much of NaCl is in 1.90 L of 0.300 M

NaCl?

Answer in units of mol.

The answer to your question is 0.57 moles

Explanation:

Data

volume = 1.9 L

[NaCl] = 0.3

moles of NaCl = ?

Process

1. - To solve this problem use the formula of Molarity.

Molarity = moles / volume (l)

-Solve for moles

moles = Molarity x volume

-Substitution

moles = 0.3 x 1.9

-Result

moles = 0.57

-Conclusion

There are 0.57 moles of NaCl in 1.90 L of a 0.3 M solution.