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10 July, 04:24

A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure was 1.00 atm, the final pressure be _ atm. Answer in 3 sig figs.

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  1. 10 July, 06:05
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    The answer to your question is P2 = 0.78 atm

    Explanation:

    Data

    Temperature 1 = T1 = 263°K Temperature 2 = T2 = 298°K

    Volume 1 = V1 = 24 L Volume 2 = V2 = 35 L

    Pressure 1 = P1 = 1 Pressure 2 = P2 = ?

    Process

    1. - To solve this problem use the Combined gas law

    P1V1/T1 = P2V2/T2

    -Solve for P2

    P2 = P1V1T2 / T1V2

    -Substitution

    P2 = (1) (24) (298) / (263) (35)

    -Simplification

    P2 = 7152 / 9205

    -Result

    P2 = 0.777

    or P2 = 0.78 atm
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