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3 April, 07:39

A sample of gas occupies a volume of 120.0 mL at a pressure of 0.75 atm and a temperature of 295 K. What will the volume be at a pressure of 1.25 atm and a temperature of 345 K?

48 mL

4 mL

8 mL

84mL

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  1. 3 April, 08:20
    0
    The answer to the question is 84

    (Step By Step Explanation).

    P1 V1/T1 = P2 V2/T2

    ::0.75 x 120/295 = 1.25 x V2/345

    90/295 = 1.25V2/345

    (cross multiply)

    1.25V2 x 295 = 90 x 345

    368.75V2 = 31050

    (divide by the coefficient of the unknown).

    368.75V2/368.75 = 31050/368.75

    V2 = 84.2. = 84

    ::The volume is 82.

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