A sample of gas occupies a volume of 120.0 mL at a pressure of 0.75 atm and a temperature of 22°C

What will the volume be at a pressure of 1.25 atm and a temperature of 70.0°C?

The is as follows

P1 V1 / T1=P2 V2/T2

where, p1=0.75, v1=120.0, T1=22, p2=1.25,

V2=?, T2=70.0

:: 0.75 x 120.0 / 22 = 1.25 x v2 / 70.0

90/22=1.25v2/70.0

(cross multiply).

1.25v2 x 22=90 x 70.0

27.5v2=6300

(divide by the coefficient of the unknown = v2).

27.5v2/27.5=6300/27.5

V2=229.090; = 229.1

:: The volume will be at 229.090 or 229.1.