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9 May, 03:26

What are the molar concentrations of the ions in 0.26 M aluminum sulfate?

C (A13+) =

C (SO4^2-) =

+3
Answers (1)
  1. 9 May, 04:41
    0
    c (Al³⁺) = 0.52 mol·L⁻¹; c (SO₄²⁻) = 0.84 mol·L⁻¹

    Explanation:

    One mole of aluminium sulfate produces 2 mol of aluminium ions and 3 mol of sulfate ions.

    If we apply the same proportionality, 0.26 mol of Al₂ (SO₄) ₃ produces 0.52 mol of Al³⁺ions and 0.84 mol of SO₄²⁻ ions.

    Al₂ (SO₄) ₃ (aq) ⟶ 2Al³⁺ (aq) + 3SO₄²⁻ (aq)

    I/mol·L⁻¹: 0.26 0 0

    C/mol·L⁻¹: - 0.26 + 0.52 + 0.84

    E/mol·L⁻¹: 0 0.52 0.84
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