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3 September, 15:42

The complete combustion of ethanol, c2h50h (fw = 46.0 g/mol), proceeds as follows: c2h50h (l) + 3 02 (g) - --→ 2 c02 (g) + 3 h20 (l) llh = - 555 kj what is the enthalpy change for combustion of 4.0 moles of c2h50h?

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  1. 3 September, 19:42
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    for 1 mol ethanol ... - 555 kj

    for 4 moles ... x = > x = - 2220kj
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