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3 November, 11:11

Calculate the solubility (in g/L) of silver carbonate in water at 25°C if the Ksp for Ag2CO3 is 8.4 x 10-12, A) 8.0 x 10-4 g/L B) 3.5 x 10-2 g/L C) 4.4 * 10-2g/L D) 5.6 x 10-2 g/L

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  1. 3 November, 12:20
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    S = 5.6 E-2 g / L

    Explanation:

    Ag2CO3 ⇔ 2Ag + CO3

    ⇒ S 2S S

    ⇒ Kps = 2S*S = 2S² = 8.4 E-12

    ⇒ S² = 8.4 E-12 / 2

    ⇒ S² = 4.2 E-12

    ⇒ S = √4.2 E-12

    ⇒ S = 2.05 E-6 mmol / mL

    ⇒ S = 2.05 E-6 mmol / mL * 0.001 mol / mmol * 275.7453 g Ag2CO3 / mol * 1000mL / L

    ⇒S = 5.651E-2 g / L
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