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30 November, 16:09

Give the coordination number for each metal ion in the following compounds:

(a) [Co (CO3) 3]3 - (note that CO32 - is bidentate in this complex) (b) [Cu (NH3) 4]2+

(c) [Co (NH3) 4Br2]2 (SO4) 3

(d) [Pt (NH3) 4][PtCl4]

(e) [Cr (en) 3] (NO3) 3

(f) [Pd (NH3) 2Br2] (square planar)

(g) K3[Cu (Cl) 5]

(h) [Zn (NH3) 2Cl2]

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  1. 30 November, 19:21
    0
    Answer: a. 6 (3x2=6)

    B. 4 (4x1=4)

    C. 6 (4 (1) + 2 (1) = 4+2=6

    D. 4

    E. 6 (3 (2) = 6)

    F. 4 (2 (1) + 2 (1) [2+2=4)

    G. 5 (5 (1) = 5)

    H. 4 (2 (1) + 2 (1) = 2+2=4)

    Explanation:

    Coordination number = no of ligands

    = No of ligands X denticity

    Denticity is nothing but type of ligands like mono, do and tetradentate ligands.
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