A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa) ?

Answer;

= 3032.15 kPa

Explanation;

Using the equation;

PV = nRT, where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol-1.

Volume = 7.5 L, T = 274 + 273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

= (5 * 0.08206 * 547) / 7.5 L

= 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

= 3032.15 kPa