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5 May, 10:30

A 94 L sample of neon gas (molar mass = 20.2 g/mol) has a mass of 44 g at a pressure of 150 kPa. What is its temperature in Kelvins?

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  1. 5 May, 12:01
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    778.96 K.

    Explanation:

    To solve these problems, we can use the general law of ideal gas: PV = nRT.

    where, P is the pressure of the gas in atm.

    V is the volume of the gas in L.

    n is the no. of moles of the gas in mol.

    R is the general gas constant (R = 0.082 L. atm/mol. K),

    T is the temperature of the gas in K.

    The temperature of the gas = PV/nR.

    P = 150.0 kPa/101.325 = 1.48 atm, V = 94.0 L, R = 0.082 L. atm/mol. K, n = mass/molar mass = (44.0 g) / (20.2 g/mol) = 2.178 mol.

    ∴ T = PV/nR = (1.48 atm) (94.0 L) / (2.178 mol) (0.082 L. atm/mol. K) = 778.96 K.
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