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27 June, 05:40

What is the volume of a 0.120 M solution that contains 9.35 g of HCI?

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  1. 27 June, 09:33
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    2.13L

    Explanation:

    first you must find the amount (mols) of HCl in the solution. then you can use that to find the volume of the solution.

    we know the:

    mass m = 9.35g

    molar mass M = 1 + 35.5=36.5 g/mol (check periodic table)

    concentration c = 0.120 mol/L

    amount (mols) of HCl:

    n = m/M

    n (HCl) = 9.35/36.5

    = 0.2561644 mol

    concentration of HCl in solution:

    n = cV

    V (HCl) = n/c

    = 0.2561644/0.120

    = 2.1347

    = 2.13 L (3sf)
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