How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

Answer: 3.68 x 10^21 particles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

Since 1 mole is the same as molar mass of a substance

237 g = 6.02 x 10^23 atoms

1.45g = Z atoms

To get the value of Z, cross multiply:

(Z atoms x 237g) = (6.02 x 10^23 atoms x 1.45g)

237Z = 8.729 x 10^23

Z = (8.729 x 10^23 / 237)

Z = 3.68 x 10^21

Thus, there are 3.68 x 10^21 representative particles in 1.45 g of the molecular compound.