What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

Question

Chemistry

Trace Spence

31 December, 00:26

What is the molarity of a solution that contains 30 grams of naoh in 500 milliliters of solution?

+5

Answers (2)

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Joshua Mack · Answer 1

Molar mass NaOH = 39.997 g/mol

number of moles solute:

n = mass of solute / molar mass

n = 30 / 39.997

n = 0.00075 moles of NaOH

Volume in liters:

500 mL / 1000 = > 0.5 L

Therefore:

M = moles of solute / volume (L)

M = 0.00075 / 0.5

M = 0.0015 mol/L

Richard · Answer 2

Answer: 1.5 M