How many grams of O2 are needed to react with 13.6 g of NH3

Mass = 32 g

Explanation:

Given dа ta:

Mass of O₂ needed = ?

Mass of NH₃ react = 13.6 g

Solution:

Chemical equation:

4NH₃ + 5O₂ → 4NO + 6H₂O

Number of moles of ammonia:

Number of moles = mass / molar mass

Number of moles = 13.6 g / 17 g/mol

Number of moles = 0.8 mol

Now we will compare the moles of ammonia and oxygen from balance chemical equation.

NH₃ : O₂

4 : 5

0.8 : 5/4*0.8 = 1

Mass of oxygen:

Mass = number of moles * molar mass

Mass = 1 mol * 32 g/mol

Mass = 32 g