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12 June, 00:04

Seven moles of Argon gas are at a presseure of 2.90 atm, and the temperature is 50c. What is the volume of the gas?

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  1. 12 June, 00:37
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    At s. t. p, the volume of a gas = 22.4dm³

    Talking the problem,

    At 1atm, 273K the volume = 7 moles * 22.4dm³/mol

    At 323K, 2.90atm, volume = ?

    The combined gas equation

    P1v1/T1=P2v2/T2

    P1=1atm

    P2=2.9atm

    T1=273K

    T2=323K

    V1=156.8dm³

    Therefore,

    1*156.8dm³/273=2.9atm*V2/323

    V2 = (156.8dm³*323K) / (273K*2.9atm)

    = 64dm³
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