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19 January, 10:04

When the volume of a gas is changed from 1145 ml to 765 ml, the temperature will change from? k to 640 k?

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Answers (2)
  1. 19 January, 11:52
    0
    The answer is: T1 = 957.91K

    Explanation:

    Hello!

    Let's solve this!

    The data we have are:

    V1: 1145ml

    V2: 765ml

    T2: 640K

    From the equation of the ideal gas, we have that the pressure is the same, the constant of the gases R is the same and the number of moles is the same.

    We match the equations and we have:

    V1 / T1 = V2 / T2

    We have to find out T1:

    T1 = (V1 * T2) / V2

    T1 = (1145ml * 640K) / 765ml

    T1 = 957.91K

    The answer is: T1 = 957.91K
  2. 19 January, 12:38
    0
    The according to the combined gas equation, the ratio of the initial volume to the initial volume should be equal to the ratio of the test volume to the test temperature, I. e, V1/T1=V2/T2

    1145ml/T1=765ml/640K

    T1 = (1145ml*640K) 765ml

    =957.91K
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