What volume of 18.0 m sulfuric acid is required to prepare 16.5 l of 0.126 m h2so4?

this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.

the dilution forumla is as follows

c1v1 = c2v2

where c1 is concentration and v1 is volume of the more concetrated solution

c2 is concentration and v2 is volume of the diluted solution

substituting the values in the equation

18.0 M x V = 0.126 M x 16.5 L

V = 0.1155 L

volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.