What is the volume of 3.00 mole of ideal gas at 100.0 C and 2.00 kPa

The volume for the ideal gas is: 4647.5 Liters

Explanation:

Formula for the Ideal Gases Law must be applied to solve this question:

P. V = n. R. T

We convert the T° to K → 100°C + 273 = 373 K

We convert pressure value from kPa to atm.

2 kPa. 1atm/101.3 kPa = 0.0197 atm

We replace data in the formula.

V = (n. R. T) / P → (3 mol. 0.082. 373K) / 0.0197 atm =

The volume for the ideal gas is: 4647.5 Liters