The reaction A (g) ⇌ 2 B (g) A (g) ⇌ 2 B (g) has an equilibrium constant of K = 0.010 K = 0.010. What is the equilibrium constant for the reaction B (g) ⇌ 1 2 A (g) ?

K = 10

Explanation:

Using Hess's law, it is possible to obtain the equilibrium constant, K, of a reaction using K of similar reactions. For example:

If A ⇄ B K = X

B ⇄ A K = 1/X

2A ⇄ 2B K = X².

Thus, if A (g) ⇄ 2B (g) K = 0.010

2B (g) ⇄ A (g) K = 1 / 0.010; K = 100

B (g) ⇄ A (g) K = √100 = 10

K = 10