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28 January, 17:38

How many joules (J) are needed to increase the temperature of 10.0 g of lead (Pb) from 30 ˚C to 50 ˚C? (Cp for Pb = 0.128 J/g˚C)

25.6 J

38.4 J

64.0 J

102.4 J

Answers (1)
  1. K
    28 January, 17:44
    0
    Q = 25.6 j

    Explanation:

    Given dа ta:

    Energy needed=?

    Mass of lead = 10.0 g

    Initial temperature = 30 °C

    Final temperature = 50°C

    Cp = 0.128 j/g.°C

    Solution:

    Specific heat capacity:

    It is the amount of heat required to raise the temperature of one gram of substance by one degree.

    Formula:

    Q = m. c. ΔT

    Q = amount of heat absorbed or released

    m = mass of given substance

    c = specific heat capacity of substance

    ΔT = change in temperature

    ΔT = 50°C - 30°C

    ΔT = 20°C

    Now we will put the values in formula.

    Q = 10 g * 0.128 j/g.°C * 20°C

    Q = 25.6 j
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