How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?

a

0.001 mL

b

none of the above

c

10 mL

d

0.10 mL

V₁ = 10 mL

Explanation:

Given dа ta:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁ = M₂V₂

M₁ = Initial molarity

V₁ = Initial volume of HCl

M₂ = Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M * V₁ = 0.10 M*300.0 mL

3.0 M * V₁ = 30 M. mL

V₁ = 30 M. mL / 3.0 M

V₁ = 10 mL