What is the empirical formula for this compound 50.05% sulfur and 49.95% oxgyen by mass?

1)

Lets take 100g of this compound.

It contains

50.05 g S and 49.95 g O.

2)

M (S) = 32.06 g/mol

M (O) = 16.00 g/mol

50.05 g S*1mol S/32.06 g S = 1.56 mol S

49.95 g O*1mol O/16.00 g O = 3.12 mol O

3) S:O =

=1.56 mol S : 3.12 mol O = (1.56 mol / 1.56 mol) : (3.12 mol / 1.56 mol) = 1:2

(mol S) : (mol O) = 1 : 2

SO2