Ask Question
3 June, 17:19

BaO2 (s) + 2HCl (aq) → H2O2 (aq) + BaCl2 (aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated with 25.0 mL hydrochloric acid solution containing 0.0272 g HCl per mL? 0.301 g H2O2 What mass of which reagent is left unreacted?

0
Answers (1)
  1. 3 June, 19:15
    0
    mass H2O2 = 0.31g H2O2

    mass unreacted = 0.0745g BaO2

    Explanation:

    Mw BaO2 = 169.33 g / mol

    Mw HCl = 36.46 g/mol

    Mw H2O2 = 34.0147 g/mol

    LR:

    ⇒ mol BaO2 = 1.50g BaO2 * mol / 169.33 g = 8.86E-3 mol BaO2 / 1 = 8.86E-3 mol BaO2

    ⇒ mol HCl = 25.0 mL * 0.0272g / mL * mol / 36.46g = 0.0186 mol HCl / 2 = 9.3E-3 mol HCl ... L. R

    mol H2O2:

    ⇒ 0.0186mol HCl * (mol H2O2 / 2mol HCl) = 9.325E-3 mol H2O2

    ⇒ g H2O2 = 9.325E-3mol H2O2 * 34.0147g H2O2 / mol H2O2 = 0.31g H2O2

    mass of wich reagent is left unreacted:

    mol that react BaO2 = 0.0186mol HCl * (mol BaO2 / 2mol HCl) = 9.3E-3mol BaO2

    mol that unreacted BaO2 = 9.3E-3 - 8.86E-3 = 4.4E-4 mol BaO2

    g unreacted BaO2 = 4.4E-4mol BaO2 * (169.33g BaO2 / mol BaO2) = 0.0745g BaO2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “BaO2 (s) + 2HCl (aq) → H2O2 (aq) + BaCl2 (aq) What mass of hydrogen peroxide should result when 1.50 g barium peroxide is treated with 25.0 ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers