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20 June, 18:48

Calculate the cell potential for the galvanic cell in which the reaction Fe (s) + Au 3 + (aq) - ⇀ ↽ - Fe 3 + (aq) + Au (s) occurs at 25 ∘ C, given that [ Fe 3 + ] = 0.00150 M and [ Au 3 + ] = 0.797 M.

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  1. 20 June, 18:58
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    0.79 V

    Explanation:

    From Nernst equation:

    E = E° - 0.0592/n log [red]/[ox]

    Number of electrons transferred=3

    [Red]=0.797 M.

    [Ox] = 0.00150 M

    First we obtain E° = 0.80 - (-0.04) = 0.84 V

    E = 0.84 - 0.0592/3 log [0.797]/[0.00150]

    E = 0.84-0.05

    E = 0.79 V
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