Adding helium to a balloon increased its volume from 358.5 ml to 2.262 l. if the final number of moles of helium in the balloon is 14.6 mol, what was the initial number of moles of helium in the balloon? assume the balloon contained only helium initially.

Question

Chemistry

Jan Shepard

13 May, 08:52

Adding helium to a balloon increased its volume from 358.5 ml to 2.262 l. if the final number of moles of helium in the balloon is 14.6 mol, what was the initial number of moles of helium in the balloon? assume the balloon contained only helium initially.

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Answers (2)

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Thompson · Answer 1

Answer : 2.31 moles of Helium was initially present in the balloon.

Explanation : Calculating the initial number of moles of helium in the balloon we need to use this method,

final moles present - 14.6 mol

Volume increased from 358.5 mL ( = 0.3585 L) to 2.26 L

(14.6 mol) x (0.3585 L / 2.26 L) = 14.6 moles X 0.158 L = 2.31 moles / L

Hence, the initial moles was 2.31 moles/L in the helium balloon.

Janiah · Answer 2

0.08 mol

Explanation:

Easy clap too lazy to add an explanation but at least I'm not wrong.