You have 100 mL of a 12M solution of HCl, and you need to dilute it to 1.5M for an experiment. How many liters will your new solution be?

800.0 mL.

Explanation:

To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.

(MV) before dilution of HCl = (MV) after dilution of HCl

M before dilution = 12.0 M, V before dilution = 100.0 mL.

M after dilution = 1.5 M, V after dilution = ? mL.

∵ (MV) before dilution of HCl = (MV) after dilution of HCl

∴ (12.0 M) (100.0 mL) = (1.5 M) (V after dilution of HCl)

∴ V after dilution of HCl = (12.0 M) (100.0 mL) / (1'.5 M) = 800.0 mL.