A beaker holds 962 g of a brine solution that is 6.20 percent salt. If 123g of water are evaporated from the beaker, how much salt must be added to have an 8.60 percent brine solution? How many grams of the 8.6% brine solution will be produced?

Question

Chemistry

Nehemiah Carroll

17 June, 04:15

A beaker holds 962 g of a brine solution that is 6.20 percent salt. If 123g of water are evaporated from the beaker, how much salt must be added to have an 8.60 percent brine solution? How many grams of the 8.6% brine solution will be produced?

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Answers (1)

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Averi · Answer 1

13.687 grams of salt should be added

The total grams of 8.6% of brine solution produced is 852.687g

Explanation:

Solution mass = 962g

Salt = 6.2%

Water = 93.8%

962 gram of water is made up of:

902.356g (due to vaporization which reduces mass)

= 902.356 - 123

= 779. 356g of water

59.644g of salt.

If we add x gram of salt for making brine solution up to 8.6%

= (59. 644g + x) g. of salt

% salt = Mass of Salt / Total mass of solution

= 0.086 = 59.644 + x / 779.356 + 59.644 + x

= 59.644 + x / 839 + x

x = 13.687 g of salt

Grams of 8.6% brine solution will be:

Gram of water + total gram of salt added to form 8.6% brine solution.

= 779.356g + 59.644g + 13.687g

= 852.687g

The total grams of 8.6% of brine solution produced is 852.687g