when mercury (II) oxide is heated it decomposes into mercury and oxygen gas how many molecules of oxygen gas are produced if 23.0g of mercury (II) oxide are heated

Answer;

= 3.1966 * 10^22 molecules of Oxygen

Explanation;

The equation for the reaction is;

2 HgO → 2 Hg + O2

Given 23 g of HgO;

Moles of HgO = 23 / 216.6 g/mol

= 0.1062 moles

Mole ratio; HgO : O2 = 2 : 1

Thus; moles of Oxygen = 0.1062 moles/2

= 0.0531 moles

But; 1 mole of oxygen = 6.02 * 10 ^23 molecules

Therefore; molecules of oxygen produced

= 6.02 * 10^23 molecules * 0.0531 moles

= 3.1966 * 10^22 molecules