Calculate delta s, delta s total when the volume of 123 g CO initially at 298K and 1 bar increased by a factor of four in (a) an adiabatic reversible expansion

0

Explanation:

we have,

T = 298K temperature

P = 1.00 bar. pressure

M = 123g. mass CO

a) Adiabatic reversible expansion

q = 0. Heat is zero

we know the total entropy change is

ΔS total = Δs + Δs surrounding

ΔS surrounding = - q / T

So, ΔS surrounding = 0

in reversible process,

ΔS = 0

Change in entropy should be positive for spontaneous process ΔS total ≥0

Therefore,

ΔS total = ΔS + ΔS surrounding

= 0

Hence, we can say that the process is not spontaneous, so the system and surrounding are in equilibrium.