How many grams of ice at 0c could be melted by the additional of 0.400 kJ of heat

To solve this we will use the formula q=mc delta T. Q is heat, m is mass, c is specific heat and delta T is change in temperature. because it is a phase change problem, temperature does not apply. Also, we will use heat of fusion of water (344J/g) instead of specific heat. We will also convert 0.400 kJ to J, which becomes 400 J.

0.400 kJ x (1000 J/1 kJ) = 400 J

400 J = (g) x (334 J/g)

g = 1.198

Because of sig figs, we will round to 1.20 grams (3 sig figs). The answer is 1.20 grams.