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24 December, 08:53

A gas that exerts a pressure of 6.20 atm in a container with a bolume of __ mL will exert a pressure of 9.150 atm when transferred to a container with a volume of 322 mL.

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  1. 24 December, 12:42
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    P1V1 = P2V2

    P1 = 6.20 atm

    V1 - ?

    P2 = 9.150 atm

    V2 = 322 mL

    6.20 atm*V1 = 9.150 atm * 322 mL

    V1=9.150 atm * 322 mL/6.20 atm ≈ 475 mL

    V1 = 475 mL
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