How many milliliters of 0.10 m pb (no3) 2 are required to react with 75 ml of 0.20 m nai? pb (no3) 2 + 2 nai - -> pbi2 + 2 nano3?

The Ml of 0.10 Pb (NO3) 2 that are required to react with 75 Ml of 0.20M Nai is 75 ml

calculation

Pb (NO3) 2 + 2Nai → Pbi2 + 2NaNo3

find the number of moles of Nai used

moles = molarity x volume in liters

volume in liters = 75/1000=0.075 moles

mole = 0.20 x0.075 = 0.015 moles

by use of mole ratio between Pb (NO3) 2 to Nai which is 1 : 2 the moles of Pb (NO3) 2 = 0.015 x1/2 = 7.5 x10^-3 moles

volume (ml)) = moles/molarity x 1000

=volume = (7.5 x10^-3) / 0.10 = 75 Ml