A gas that has a pressure of 2 atm and

a volume of 10 L. What would be the

new volume if the pressure was

changed to 1 atm?

The answer to your question is 20 liters

Explanation:

Data

Pressure 1 = P1 = 2 atm

Volume 1 = V1 = 10 l

Pressure 2 = P2 = 1 atm

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (2 x 10) / 1

-Simplification

V2 = 20/1

-Result

V2 = 20 l