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26 November, 18:18

A balloon that had a volume of 3.5 L at 25.0 C is placed in a hot room at 40.9 C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the room?

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  1. 26 November, 20:36
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    V1/T1 = V2/T2

    V1 = 3.5 L

    T1 = 25 + 273=298 K

    T2 = 40.9 + 273 = 313.9 K

    V2-?

    3.5 L/298 K = V2 / 313.9 K

    V2 = (3.5 L*313.9 K) / 298 K ≈ 3.69 L
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