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23 November, 04:31

A 4.700 L sample of gas is cooled from 71.0 °C to a temperature at which its volume is 3.300 L. What is this new temperature? Assume no change in pressure of the gas.

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  1. 23 November, 07:24
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    initial condition : Vi = 4.700 L, Ti = 71.0ºC + 273 = > 344 K

    final condition : Vf = 3.300 L, Tf = ?

    Pressure is constant:

    According to charle's law, volume is directly proportional to temperature at constant pressure!

    Hence Vi / Ti = Vf / Tf

    4.700 L / 344 K = 3.300 L / Tf

    Tf = 3.300 L * 344 K / 4.700 L

    Tf = 1135200 / 4.700

    Tf = 241.53 K

    Tf = 241.53 - 273

    Tf = - 31.47ºC
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