2. Calculate the number of grams of nitrogen dioxide that are produced from 4 moles of nitric oxide.

2NO (g) + O2 (g)  2NO2 (g)

mass of nitrogen dioxide = 368g

Explanation:

From the equation:

2 moles of NO = 2 moles of 2 NO2

4 moles of NO = x moles of NO2

x = (2 * 4) / 2 = 8/2 = 4 moles of NO2

No. of moles = reacting mass / molecular weight

Reacting mass = No. of moles * molecular weight

Reacting mass = 4 * 92 = 368g