For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m; [h2] = 0.420 m; [n2] = 0.800 m. give the equilibrium constant expression and use it to calculate the constant. 2 nh3 (g) 3 h2 (g) + n2 (g)

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Chemistry

Boss

18 December, 20:35

For the reaction below, the equilibrium concentrations were found to be [nh3] = 0.250 m; [h2] = 0.420 m; [n2] = 0.800 m. give the equilibrium constant expression and use it to calculate the constant. 2 nh3 (g) 3 h2 (g) + n2 (g)

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Dillon Cuevas · Answer 1

Equation for the decomposition of ammonia:

2NH3->N2+3H2

Equilibrium constant for this equation will be:

Kc=[N2] ([H2]^3) / [NH3]^2

As given Concentration of N2=0.800 M

Concentration of H2=0.420 M

Concentration of NH3=0.250 M

So Kc = ([0.420]^3) * (0.8) / ([0.250]^2)

= 0.9483264

so equilibrium constant will be:

0.9483264