C4H4O62 - (aq) + 2 MnO4 - (aq) + 8 H3O + (aq) → 2 Mn2 + (aq) + 4 CO2 (g) + 14 H2O (l)

element being reduced

element being oxidized

I really do not understand how to do this at all

Question

Chemistry

David Mullen

8 May, 11:49

C4H4O62 - (aq) + 2 MnO4 - (aq) + 8 H3O + (aq) → 2 Mn2 + (aq) + 4 CO2 (g) + 14 H2O (l)

element being reduced

element being oxidized

I really do not understand how to do this at all

+4

Answers (1)

Know the Answer?

Jovani Jordan · Answer 1

Oxidized is that which goes up in oxidation number. The Fe goes from + 2 to + 3. Reduced goes down. Mn goes from + 7 to + 2. The oxidizing agent gets reduced. Mn. The reducing agent gets oxidized.

C4H4O62 - (aq) + 2 MnO4 - (aq) + 8 H3O + (aq) → 2 Mn2 + (aq) + 4 CO2 (g) + 14 H2O (l)element being reducedelement being oxidizedI really do not understand how to do this at all

C4H4O62 - (aq) + 2 MnO4 - (aq) + 8 H3O + (aq) → 2 Mn2 + (aq) + 4 CO2 (g) + 14 H2O (l)

element being reduced

element being oxidized

I really do not understand how to do this at all