If the solubility of copper chloride (CuCl2) is 151 g/dm3, how much copper chloride can be dissolved in 7.8 dm3 of water?

1,200 g (rounding to two significant figures).

Explanation:

1) dа ta:

a) S = 151 g/dm³

b) mass = x

c) V = 7.8 dm³³

2) Formula for solubility, S:

S = mass of solute / volume of solvent.

3) Solution:

Substitute the data into the formula:

151 g / dm³ = x / 7.8 dm³

Solve for x:

x = 151 g/dm³ * 7.8 dm³ = 1,177.8 g.

Round to two significant figures (7.8 dm³ has two sig. fig.) : 1,200 g