A sample of neon experiences a pressure drop from 75 kPa to 53 kPa. The temperature increases from 27ºC to 93ºC. If the initial volume is 12 L, what is the final volume?

V2 = 20.71L

Explanation:

P1 = 75kPa = 75*10³Pa

P2 = 53kPa = 53*10³Pa

T1 = 27°C = (27 + 273.15) K = 300.15K

T2 = 93°C = (93 + 273.15) K = 366.15K

V1 = 12L

V2 = ?

From combined gas equation,

P1*V1 / T1 = P2*V2 / T2

P1*V1*T2 = P2*V2*T1

Solve for V2

V2 = P1*V1*T2 / P2*T1

V2 = (75*10³ * 12 * 366.15) / (53*10³ * 300.15)

V2 = 329535000 / 15907950

V2 = 20.71

The final volume is 20.71L