A solution has pOH 5.9

A) What is the [OH-]?

B) What is the [H3O+]?

C) Is this acidic, alkaline, or neutral?

The answer to your question is below

Explanation:

Data

pOH = 5.9

a) [OH⁻] = ?

pOH measures the [OH⁻]

Formula

pOH = - log[OH⁻]

-Substitution

5.9 = - log[OH⁻]

[OH⁻] = antilog (-5.9)

-Result

[OH⁻] = 1.26 x 10⁻⁶ M

b) [H₃O⁺]

pH + pOH = 14

-Solve for pH

pH = 14 - pOH

-Substitution

pH = 14 - 5.9

-Result

pH = 8.1

-Calculate [H₃O⁺]

pH = - log[H₃O⁺]

-Substitution

8.1 = - log[H₃O⁺]

[H₃O⁺] = antilog (-8.1)

-Result

[H₃O⁺] = 7.9 x 10⁻⁹ M

c) This solution is alkaline because the pH is higher than 7.

The answer is A

A. Poh 5.9