Calculate the moles of new H₂ O₂ using the balanced formula below and the average moles of KMnO₄ from calculation #2.

The average moles of KMnO₄ is 0.90mol.

2KMnO₄ + 5H₂O₂ + 3H₂SO₄ → K₂SO₄ + 2MnSO₄ + 8H₂O + 5O₂

Edit: I got 2.25mol, can anyone confirm this?

Answer is 2.25 mol.

Explanation;

The balanced reaction equation is

2KMnO₄ + 5H₂O₂ + 3H₂SO₄ → K₂SO₄ + 2MnSO₄ + 8H₂O + 5O₂

The stoichiometric ratio between KMnO₄ and H₂O₂ is 2 : 5.

Hence,

moles of reacted H₂O₂ = moles of KMnO₄ reacted x (5/2)

= 0.90 mol x (5/2)

= 2.25 mol

Hence, your answer is correct.